Except that your logarithms can have any consistent base, including 2. So I don'... | Hacker News

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		Nevermark on May 15, 2023 \| parent \| context \| favorite \| on: random(random(random(random()))) Except that your logarithms can have any consistent base, including 2. So I don't think using a logarithm to introduce a special dependence on e is warranted in this case.

sobellian on May 15, 2023 [–]

Well the expected value of E[log2(rand())] is not the same as E[log(rand())] and therein lies the difference. See my sibling comment.

Like I said, you can check this in a python terminal.

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