Hacker Newsnew | past | comments | ask | show | jobs | submitlogin

As arethuza said.

Obviously there would be plenty of questions, ranging from the most basic (a CD released in 1990 contains 'x' MB of data on it... but there's also the sleeve design, printed track listing etc...) to more complex (how do you measure the data of a painting in computer terms?), but I'm sure if someone were to set about trying to work this out, they could think up (albeit debatable) definitions.



It's actually not all that difficult to measure the data of a painting in computer terms: get a high resolution scan and store it as a JPEG. Of course, this is open to some reasonable disagreements about what constitutes a "high resolution", but the basic principle applies. I'd suspect that it won't make a huge difference, since audio recordings take up roughly an order of magnitude* more space than still images, and video roughly an order of magnitude more information than audio.

* I have no substantiation for this, but it seems about right: a JPEG is a megabyte or 2, while a single movement of a symphony is 10 or 20, and a short movie at reasonably high quality is easily 100 MB.


That depends on what you call a high res img.

Worst case: http://articles.cnn.com/2007-10-17/us/monalisa.mystery_1_leo...

150,000 dots per inch, 13 light spectrums, including ultra- violet and infrared at say 10 bit per spectrum * largest painting in the world (12 384 000 square inches) http://www.msnbc.msn.com/id/14309591/ns/world_news-weird_new...

150 000 x 150 000 x 13 x 12 x (12 384 000 bits) = 4.71279266 exabytes




Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: